Algorithm & Flowchart Determining Numbers 100 divisible
by 3 & 5
v Flowchart:
v Description
of:
1. Advance
from the start.
2. Then we
give control of the control input with "i ß 0".
3. Our input
recurrence (Looping).
4. After that
we specify the first conditioning: "i> 100".
5. After the
conditioning of both: "i% 3 = 1 and i% 5 = 1".
6. but if the conditioning value "no"
then the output will be in print as "i" and will be entered in the
processing of "i ß i +15"
If the conditioning value "yes" then it will be entered in the processing
of "i ß i
+15".
7. The process
will continue until the "i> 100" trsbt met.
8. Completed.
v Syntax C +
+:
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# Include <iostream>
# Include <string>
using namespace std;
int main ()
{
int i;
i = 0;
while (! (i> 100))
{
if (i% 3 == 1 && i% 5 == 1)
{
}
else
{
cout << i
<< endl;}
i = i +15;
}
system ("PAUSE");
return 0;
}
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v Syntax C +
+ with Class structure:
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# Include <cstdlib>
# Include <iostream>
using namespace std;
class number {
friend ostream & operator <<
(ostream &, & number);
friend istream & operator >>
(istream &, & number);
public:
number () {};
void process () {
i =
0;
while
(! (i> 100))
{If
(i% 3 == 1 && i% 5 == 1) {
}
else
{
cout << i
<< endl;}
i = i +15;
}
}
private:
int
i;
};
istream & operator >> (istream & in, & enter the numbers) {
cout << "Numbers divisible by 3 & 5
=" << endl;
in >> masukkan.i;
return in;
}
ostream & operator << (ostream & out, numbers & output) {
cout << "Bilangannya is" <<
keluaran.i << endl;
return out;
}
int main (int argc, char * argv [])
{
number bil;
cin >> bil;
bil.proses ();
cout << bil;
cout << endl;
system ("PAUSE");
return 0;
}
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Algorithm & Flowchart Determining Build space [square / rectangle]
v Flowchart:
v Description of:
1. Advance
from the start.
2. We have
input the length of the first.
3. After
that we have input width.
4. And we set
pengkondisiaannya with input "p = l".
5. If the
conditioning value "yes" then it will go in processing the
"PUT" Wake Such is the Square "and in outputkan.
6. But if the
conditioning value "no" then the output will be processed sbgmana
"PUT" Wake Such is the Rectangle ".
7. Completed.
v Syntax C + +:
|
# Include <iostream>
# Include <string>
using namespace std;
int main ()
{
raptor_prompt_variable_zzyz string;
int p;
int l;
raptor_prompt_variable_zzyz = "Enter the
length:";
cout << endl << raptor_prompt_variable_zzyz;
cin >> p;
raptor_prompt_variable_zzyz = "Put L:";
cout << endl << raptor_prompt_variable_zzyz;
cin >> l;
if (p == l)
{
cout << "Build Such is the
square" << endl;}
else
{
cout << "Build Such is the
Rectangle" << endl;}
system ("PAUSE");
return 0;
}
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v Syntax C + + with Class structure:
|
# Include <cstdlib>
# Include <iostream>
using namespace std;
bngn_ruang class {
friend ostream & operator <<
(ostream &, bngn_ruang &);
friend istream & operator >>
(istream &, bngn_ruang &);
public:
bngn_ruang () {};
void process () {
if (p == l)
{
result = "Wake Such is the Square";}
else result = "Wake Such is the Rectangle";
}
private:
int
p;
int
l;
char
* result;
};
istream & operator >> (istream & in, bngn_ruang & insert) {
cout << "Enter the length:" <<
endl;
in >> masukkan.p;
cout << "Enter the width:" <<
endl;
in >> masukkan.l;
return in;
}
ostream & operator << (ostream & out, bngn_ruang & output)
{
cout << "The output is as follows:"
<< endl << keluaran.hasil;
return out;
}
int main (int argc, char * argv [])
{
bngn_ruang space;
cin >> space;
ruang.proses ();
cout << space;
cout << endl;
system ("PAUSE");
return 0;
}
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